Blanket Math

  
I’m making the Husband a blanket for Xmas. 
It’s not a secret, he knows, mostly because I had to use the entire dining room to parse out the yard into measured piles (which I then tied together and rolled into balls) in order to get the multicolored look. He’s very, very aware. The sorting of the yarn will be sung about for years to come. 

I’ve never crocheted a full size blanket, it’s hard work and takes lots of yarn. But I’m excited about doing this blanket because I think hubby will love it dearly, especially if I pull it off the way I intend. I’m making most of it multicolored, from 4 different balls of faux chinelle yarn, then a stripe each of the main colors, brown, grey, and blue. I think it will come out looking awesome, unique, and not too grandma-esque. I have six balls of multicolored yarn now (made from 4 skeins), the first ball made about ten inches of blanket, so if:

skeins are x

Balls are y

4x=6y

y=10(inches)

So x=15(inches)

So if I want a 5’x7′ blanket, I need two more skeins of yarn….I guess I’ll go with blue and grey. I hope the damn thing is wide enough…but too late to start again now, I’ve got nearly a foot of length, and the width is my armspan. My hands cross when I hug hubby, so armspan should be wide enough. Right?

Anyway, it’s about 5.5 feed wide, and I believe that will be enough.
  
Lots to ponder, loyal reader. This blanket math is rough.